AEVA Homepage
Forum Home Forum Home > Technical Discussion > Batteries, charging, management and monitoring
  Active Topics Active Topics
  FAQ FAQ  Forum Search   Register Register  Login Login

Li cell discharge tests

 Post Reply Post Reply Page  123>
Author
Message
  Topic Search Topic Search  Topic Options Topic Options
Nevilleh View Drop Down
Senior Member
Senior Member
Avatar

Joined: 15 January 2009
Location: Tauranga NZ
Online Status: Offline
Posts: 470
  Quote Nevilleh Quote  Post ReplyReply Direct Link To This Post Topic: Li cell discharge tests
    Posted: 16 July 2009 at 1:20pm
Still waiting for my SE cells to arrive, hopefully tomorrow, so in the meantime I built a test rig based on the water cooled load I saw on here somewhere!
I hooked up a Thunder Sky LFP40AH cell and did a 120 A discharge test. I used a Nangfeng contactor, courtesy of Zeva to keep it all safe, a Radio Shack 4 1/2 digit DMM to measure the cell voltage (4-wire) and a Jaycar Clamp Ammeter to measure the current. Here's the numbers for those who are interested:

Thunder Sky LFP40AH Discharge test               
Time     Volts          Amps
0     3.571          132
1     3.01          125
2     2.995          123
3     2.99          122
4     2.988          122
5     2.988          121
6     2.989          120
7     2.987          119
8     2.984          119
9     2.98          119
10     2.976          119
11     2.967          120
12     2.964          119
13     2.954          118
14     2.948          118
15     2.941          118
16     2.932          118
17     2.919          118
18     2.9          118
19     2.881          117
20     2.85          116
21     2.802          114
22     2.728          112
23     2.591          107
24               
25               

Had to keep adding water to try and keep the current fairly constant - it got pretty warm.
The cell itself felt barely warm to the touch at the end of the test.
As soon as I get a SE cell, I'll set it up on the same rig and give it a try.
Tried to upload a photo, but got "Permission Denied"

Back to Top
coulomb View Drop Down
Senior Member
Senior Member
Avatar

Joined: 22 January 2009
Location: Brisbane
Online Status: Offline
Posts: 1460
  Quote coulomb Quote  Post ReplyReply Direct Link To This Post Posted: 16 July 2009 at 2:03pm
With respect to the "Permission denied" problem: check this post of mine from a week or two ago:

http://www.aeva.asn.au/forums/forum_posts.asp?TID=1298

Edited by coulomb - 04 August 2009 at 11:06am
Working with Weber on converting an MX-5
Back to Top
coulomb View Drop Down
Senior Member
Senior Member
Avatar

Joined: 22 January 2009
Location: Brisbane
Online Status: Offline
Posts: 1460
  Quote coulomb Quote  Post ReplyReply Direct Link To This Post Posted: 16 July 2009 at 2:08pm
Originally posted by Nevilleh

Had to keep adding water to try and keep the current fairly constant - it got pretty warm.

I think you might need some more water; we use about 1.5 litres. I guess we could use a bit more. We find that stirring the water also keeps the current up a bit. I guess the ultimate would be a 4L ice cream container with a small motorised stirrer.
Working with Weber on converting an MX-5
Back to Top
coulomb View Drop Down
Senior Member
Senior Member
Avatar

Joined: 22 January 2009
Location: Brisbane
Online Status: Offline
Posts: 1460
  Quote coulomb Quote  Post ReplyReply Direct Link To This Post Posted: 16 July 2009 at 2:11pm
As a point of interest, that works out to about 4.3 mR internal resistance, or 173 mV/C for capacity independence (just multiply internal resistance by the capacity in Ah). BTW, the C here isn't degrees centigrade, it's the number 40 for a 40 Ah cell. This agrees rather well with a measurement of 171 mV/C on our TS 40 Ah cell. Yours was possibly a little colder than ours.
Working with Weber on converting an MX-5
Back to Top
Nevilleh View Drop Down
Senior Member
Senior Member
Avatar

Joined: 15 January 2009
Location: Tauranga NZ
Online Status: Offline
Posts: 470
  Quote Nevilleh Quote  Post ReplyReply Direct Link To This Post Posted: 17 July 2009 at 5:38am
Originally posted by coulomb

Permission denied: check this post of mine from a week or two ago:

http://www.aeva.asn.au/forums/forum_posts.asp?TID=1298


Thanks for the tip. I did take a long time as I had to download the picture, open Photoshop to squash it up and then try and upload it. I'll get everything ready before trying next time.
Back to Top
Nevilleh View Drop Down
Senior Member
Senior Member
Avatar

Joined: 15 January 2009
Location: Tauranga NZ
Online Status: Offline
Posts: 470
  Quote Nevilleh Quote  Post ReplyReply Direct Link To This Post Posted: 17 July 2009 at 5:49am
Originally posted by coulomb

As a point of interest, that works out to about 4.3 mR internal resistance, or 173 mV/C for capacity independence (just multiply internal resistance by the capacity in Ah). BTW, the C here isn't degrees centigrade, it's the number 40 for a 40 Ah cell. This agrees rather well with a measurement of 171 mV/C on our TS 40 Ah cell. Yours was possibly a little colder than ours.


Did you calculate the internal resistance by taking the V drop from the 3.57 figure?
That high initial voltage seems to be due to some sort of "surface charge" effect similar to a PbA battery and the rapid voltage drop occurs because of this charge dissipating rather than being lost across the internal resistance. This is just speculation on my part, of course! But the cell stabilises at around 3.2v with no load - I quickly turned the load off and back on again to see what the cell voltage would do. So if I take the no load volts as 3.2 and the 120A load voltage as 3.0, then that .2v is dropped across the cell internal resistance which then works out as .2/120 = 1.67 milliohms
Does that make sense to you?
But I think it is pretty good that you can draw 3C with only a .2v drop.

The room (garage!)temp where the cells have been sitting for a few weeks was about 17 deg C.

If the SE cells are similar, that gives me hope!

Edit: If I take the current as 120A for 23 minutes, that equals 46 AH.


Edited by Nevilleh - 17 July 2009 at 5:53am
Back to Top
Nevilleh View Drop Down
Senior Member
Senior Member
Avatar

Joined: 15 January 2009
Location: Tauranga NZ
Online Status: Offline
Posts: 470
  Quote Nevilleh Quote  Post ReplyReply Direct Link To This Post Posted: 17 July 2009 at 6:06am

Here's a picture of my test setup and the water-cooled load! (Thanks Coulomb)



The Power Supply on the right is 12v for the contactor which is just behind it.



Edited by Nevilleh - 17 July 2009 at 6:08am
Back to Top
coulomb View Drop Down
Senior Member
Senior Member
Avatar

Joined: 22 January 2009
Location: Brisbane
Online Status: Offline
Posts: 1460
  Quote coulomb Quote  Post ReplyReply Direct Link To This Post Posted: 17 July 2009 at 6:14am
Originally posted by Nevilleh

Did you calculate the internal resistance by taking the V drop from the 3.57 figure?

Yes, I did.

That high initial voltage seems to be due to some sort of "surface charge" effect similar to a PbA battery and the rapid voltage drop occurs because of this charge dissipating rather than being lost across the internal resistance.

Yes, it's a good idea to "blow off" this initial charge somehow. Perhaps a 10 second burst at 3C, but then wait a few minutes fot the voltage to "settle up".

But the cell stabilises at around 3.2v with no load - I quickly turned the load off and back on again to see what the cell voltage would do. So if I take the no load volts as 3.2 and the 120A load voltage as 3.0, then that .2v is dropped across the cell internal resistance which then works out as .2/120 = 1.67 milliohms
Does that make sense to you?

Yes, that's the basic idea. But you can't take two unrelated figures like that; you have to have one just before a load, and one just after (perhaps after 5 seconds as we do) the load is applied. The voltages vary too much with SOC and temperature to just take two figures as you seem to have.

If you did a test and it really went from 3.2 to 3.0 at 120A, then indded you have 1.7 mR, or 67 mV/C. But this is about 40% (at 18°C) or half (at 30°C) what we have found, so I doubt that you would find a pair like that.

But I think it is pretty good that you can draw 3C with only a .2v drop.

Yes, it would be.

Edit: If I take the current as 120A for 23 minutes, that equals 46 AH.

I think your current sagged too much at the end (closer to 100A) to say that. You need to find the average discharge current (use fairly big blocks of time, like 4-5 minutes) for the capacity calculation.
Working with Weber on converting an MX-5
Back to Top
Nevilleh View Drop Down
Senior Member
Senior Member
Avatar

Joined: 15 January 2009
Location: Tauranga NZ
Online Status: Offline
Posts: 470
  Quote Nevilleh Quote  Post ReplyReply Direct Link To This Post Posted: 17 July 2009 at 6:27am
Originally posted by coulomb


If you did a test and it really went from 3.2 to 3.0 at 120A, then indded you have 1.7 mR, or 67 mV/C. But this is about 40% (at 18°C) or half (at 30°C) what we have found, so I doubt that you would find a pair like that.


The advantage of using a contactor was that I could switch the load off and on at will. I turned it off for a few seconds at each minute and observed the cell voltage rise which is why I said that it stabilised around 3.2v (after 3 minutes). This technique also means that I am measuring the voltage before and after applying the load, as you said.
It does seem to me that this figure is realistic, reflecting the actual voltage drop under load whereas using a figure of 4.3 milliohms does not give the observed performance.
The cell was charged to 3.65v only, not the 4.2v recommended by TS.
If you look at their published discharge curves, you will see that around 3.2v at .3C discharge is the plateau which is reached after 20% discharge and this correlates quite closely with what I measured.


Edited by Nevilleh - 17 July 2009 at 6:35am
Back to Top
Nevilleh View Drop Down
Senior Member
Senior Member
Avatar

Joined: 15 January 2009
Location: Tauranga NZ
Online Status: Offline
Posts: 470
  Quote Nevilleh Quote  Post ReplyReply Direct Link To This Post Posted: 17 July 2009 at 6:52am
Originally posted by coulomb


I think your current sagged too much at the end (closer to 100A) to say that. You need to find the average discharge current (use fairly big blocks of time, like 4-5 minutes) for the capacity calculation.


Assuming the current was constant for each minute interval - which is more accurate than taking 4 or 5 minute blocks, by the way - the average amp-minutes was 118.35, so the cell capacity is 45.37 AH at that discharge rate.


Edited by Nevilleh - 17 July 2009 at 6:54am
Back to Top
coulomb View Drop Down
Senior Member
Senior Member
Avatar

Joined: 22 January 2009
Location: Brisbane
Online Status: Offline
Posts: 1460
  Quote coulomb Quote  Post ReplyReply Direct Link To This Post Posted: 17 July 2009 at 7:00am
Oh, right! I thought you just used 120A as the current. Well done.
Working with Weber on converting an MX-5
Back to Top
weber View Drop Down
Senior Member
Senior Member
Avatar

Joined: 23 January 2009
Location: Brisbane
Online Status: Offline
Posts: 650
  Quote weber Quote  Post ReplyReply Direct Link To This Post Posted: 17 July 2009 at 10:21am
Originally posted by Nevilleh

The advantage of using a contactor was that I could switch the load off and on at will.

Advantage of a contactor as compared to what? Surely you need _some_ device designed to switch under load, and won't _any_ such device allow you to switch at will?

We use a parallelled multi-pole circuit breaker which gives short-circuit protection as well as switching under load (although of course not protection against a short at the cell terminals). You're living more dangerously in that regard. I recommend using a fuse with your contactor.

I turned it off for a few seconds at each minute and observed the cell voltage rise which is why I said that it stabilised around 3.2v (after 3 minutes). This technique also means that I am measuring the voltage before and after applying the load, as you said.
It does seem to me that this figure is realistic, reflecting the actual voltage drop under load whereas using a figure of 4.3 milliohms does not give the observed performance.


This definitely needs more research and thought, to come up with an easily repeatable voltage sag test that bears some resemblance to actual use in an EV.

1. A voltage-sag or internal resistance figure is utterly meaningless if you don't know the internal temperature of the cell at the time. The figures can almost halve with a temperature increase of only about 10 degrees Celsius. One day we'll have the relationship worked out so we only need figures at one or two temperatures and we can predict it at any other.

2. If you're running a continuous 3C discharge on a Thunder Sky (or most LiFePO4s) then you're rapidly heating the cell internally (particularly at the beginning) and this won't be measurable on the outside of cell until maybe 10 minutes later.

So we are turning the 3C on for a few seconds at a known stabilised temperature, whereas you are turning it off for a few seconds at an unknown, rapidly increasing temperature, which is much higher than you could be measuring on the outside of the case (or on the terminals, given the massive heatsinking by the cables).
Working with Coulomb on converting an MX-5
Back to Top
acmotor View Drop Down
AEVA Member
AEVA Member
Avatar

Joined: 25 April 2007
Location: Perth,Australia
Online Status: Offline
Posts: 2472
  Quote acmotor Quote  Post ReplyReply Direct Link To This Post Posted: 17 July 2009 at 11:00am
weber, can you short your load and see if the CB trips ?   
Would a fuse blow in this application ?

Just thinking on the relevance of these tests to the EV....
Nevilleh method (resistance measurement at turn off ?) is what I would want to know since my cells (other than first few minutes of the drive) would likely be in Tamb(internal)(nev) condition.
Perhaps there is common ground.

weber, you will probably explode back ! but any tests you guys end up with comparing cells need to be very EV application appropriate. (App.ev.) That is not to say tests so far aren't. Just kept it in mind.

Red Suzi   
3PIM, the workhorse of industry and now the racehorse of transportation.
Back to Top
weber View Drop Down
Senior Member
Senior Member
Avatar

Joined: 23 January 2009
Location: Brisbane
Online Status: Offline
Posts: 650
  Quote weber Quote  Post ReplyReply Direct Link To This Post Posted: 17 July 2009 at 11:44am
Originally posted by acmotor

weber, can you short your load and see if the CB trips ?   

Wouldn't we risk damaging the cell? I'll discuss it with Coulomb. It would be good to know for sure.

Would a fuse blow in this application ?

If it's sized correctly and the cell isn't flat I would expect it to do so after a few seconds. Didn't you say your fuses were _only_ good for short circuit protection and you rely on your drive for overcurrent protection? Hmm. I guess the difference here is that the resistance of the protection device itself may be quite significant when there is only 3 volts behind it. Good point.

Just thinking on the relevance of these tests to the EV....
Nevilleh method (resistance measurement at turn off ?) is what I would want to know since my cells (other than first few minutes of the drive) would likely be in Tamb(internal)(nev) condition.


Really? I seem to remember you writing elsewhere that a 3C continuous discharge was irrelevant to you, since you had no intention of flattening your battery in 20 minutes. That's what Nevilleh is doing in this test.

Perhaps there is common ground.

Isn't the aim to be able to predict what the voltage sag will be, given the brand of cell, the current and the temperature (and maybe the approx SoC)?

weber, you will probably explode back !

You've got me all wrong. Ask Coulomb how often I explode. The only part of your post that I could possibly find offensive is the above sentence itself, which could lead to a vicious cycle, so I won't.

but any tests you guys end up with comparing cells need to be very EV application appropriate. (App.ev.) That is not to say tests so far aren't. Just kept it in mind.

Isn't that what I said in my previous post in this thread?

Oh damn. I'm doing it again. Being right. Sorry. I just can't help myself.

The main thing is, if you do some measurement of sag or internal resistance, make sure you tell us exactly how you measured it. e.g. what the cell temperature was and what the cell was doing in the 20 or so minutes before the test, and maybe what its temperature got up to in the 20 or so minutes after the test.
Working with Coulomb on converting an MX-5
Back to Top
Nevilleh View Drop Down
Senior Member
Senior Member
Avatar

Joined: 15 January 2009
Location: Tauranga NZ
Online Status: Offline
Posts: 470
  Quote Nevilleh Quote  Post ReplyReply Direct Link To This Post Posted: 17 July 2009 at 11:54am
It's all interesting stuff, isn't it?
I am trying to simulate the load an EV would put on the thing by running it at 3C and then "lifting off" monetarily with the cells at "garage" temperature, ie 17 deg C. Now I stand by my internal resistance measurement of 1.67 milliohms and the amount of heat generated in the cell then is 120 x 120 x 1.67 x 10^-3 = 24 watts. Don't know what the Specific Heat of the internal chemicals is, but if it were water and the weight is say 1.5 kg, then 24 watts applied for 23 minutes will raise its temperature by 5.26 deg C. Not a huge heat rise, is it?
Solid Li and Ethanol (might not be relevant, but we can always drink it )both have specific heats of about half that of water, so if the thing is built out of that sort of stuff, the temp rise would be about double, or say 10 - 11 deg C. Enough to have quite an effect, according to Coulomb. But it does drop the internal res, so that can only be good.
Still no sign of my SE cells, can't wait to do a comparison.

Just as an aside, I am using 135 cells wired as 3 parallel cell blocks with 45 such blocks in series. ie 45 x 120 AH blocks. I am doing this for 2 reasons: 1) the 120 AH cell is too tall to fit in my available space, and 2) I hope one day to shift to an ac motor and I can then use my 135 cells in series to get most of the way to the required voltage.

If these things deliver 3C with only a .2V drop , I can suck 360A at 3V out of my cells, ie the output power is 3v x 45 x 360A = 48.6 kW. That can be drawn for 23 minutes!
Back to Top
acmotor View Drop Down
AEVA Member
AEVA Member
Avatar

Joined: 25 April 2007
Location: Perth,Australia
Online Status: Offline
Posts: 2472
  Quote acmotor Quote  Post ReplyReply Direct Link To This Post Posted: 17 July 2009 at 11:55am
Probably a lot less than 3V

Perhaps more predictable than right, but not often wrong. That is a compliment. You are valued !

Maybe it is time to slip a thermocouple inside the cell. After all, you talked me into fitting one to the little motor ?
Red Suzi   
3PIM, the workhorse of industry and now the racehorse of transportation.
Back to Top
acmotor View Drop Down
AEVA Member
AEVA Member
Avatar

Joined: 25 April 2007
Location: Perth,Australia
Online Status: Offline
Posts: 2472
  Quote acmotor Quote  Post ReplyReply Direct Link To This Post Posted: 17 July 2009 at 11:59am
OOps leap frog post there. The 3V applied to weber's fuse blow topic.
I know, I should have quoted.
Red Suzi   
3PIM, the workhorse of industry and now the racehorse of transportation.
Back to Top
Nevilleh View Drop Down
Senior Member
Senior Member
Avatar

Joined: 15 January 2009
Location: Tauranga NZ
Online Status: Offline
Posts: 470
  Quote Nevilleh Quote  Post ReplyReply Direct Link To This Post Posted: 17 July 2009 at 12:05pm
Originally posted by weber



1. A voltage-sag or internal resistance figure is utterly meaningless if you don't know the internal temperature of the cell at the time. The figures can almost halve with a temperature increase of only about 10 degrees Celsius. One day we'll have the relationship worked out so we only need figures at one or two temperatures and we can predict it at any other.

2. If you're running a continuous 3C discharge on a Thunder Sky (or most LiFePO4s) then you're rapidly heating the cell internally (particularly at the beginning) and this won't be measurable on the outside of cell until maybe 10 minutes later.



Self-contradictory! How can it be "utterly meaningless" in one sentence and "almost halve" in the next?
I might try some tests at different temperatures, but there is NOT a lot of rapid heating in the cell at 3C.
Back to Top
acmotor View Drop Down
AEVA Member
AEVA Member
Avatar

Joined: 25 April 2007
Location: Perth,Australia
Online Status: Offline
Posts: 2472
  Quote acmotor Quote  Post ReplyReply Direct Link To This Post Posted: 17 July 2009 at 12:10pm
Maybe "hard to reconcile" rather than utterly meaningless ?

k type thermocouple multimeters are cheap.
Red Suzi   
3PIM, the workhorse of industry and now the racehorse of transportation.
Back to Top
Nevilleh View Drop Down
Senior Member
Senior Member
Avatar

Joined: 15 January 2009
Location: Tauranga NZ
Online Status: Offline
Posts: 470
  Quote Nevilleh Quote  Post ReplyReply Direct Link To This Post Posted: 17 July 2009 at 12:17pm
Of course, I forgot that weber is "always right".
He says he is, so he must be, or he wouldn't be? Almost an Einsteinian paradox?
But a thermocouple would be pointless as it could only measure the cell temp on the outside and the massive heating is on the inside, and heat sink-ed away by the huge terminals before it can be measured!
Back to Top
weber View Drop Down
Senior Member
Senior Member
Avatar

Joined: 23 January 2009
Location: Brisbane
Online Status: Offline
Posts: 650
  Quote weber Quote  Post ReplyReply Direct Link To This Post Posted: 17 July 2009 at 12:37pm
Originally posted by Nevilleh

Of course, I forgot that weber is "always right".
He says he is, so he must be, or he wouldn't be? Almost an Einsteinian paradox?

I'm a bit worried that there was no smiley or winky after that. I hope you are aware that it was ACmotor who joked recently that I make him mad because I'm always right. This was in the thread on rewiring an induction motor. I was just playing along with his joke and making fun of myself. I guess I'd better stop that particular line.

See what trouble you've got me into now, ACmotor.
Working with Coulomb on converting an MX-5
Back to Top
Tritium_James View Drop Down
AEVA Member
AEVA Member

AEVA Corporate Member

Joined: 04 March 2009
Online Status: Offline
Posts: 520
  Quote Tritium_James Quote  Post ReplyReply Direct Link To This Post Posted: 17 July 2009 at 12:44pm
The correct way to do this sort of testing would be with a programmable load and a standard drive cycle test curve. Then we can all argue about which standard drive cycle is appropriate!

But since it seems nobody has a programmable load, then I guess we're stuck with the method here. I'm not sure which type is better, I guess it depends on what you're trying to find (duh!). I think the 'start at room temp and hit it with a big current for 5 seconds' is probably what I'm most interested in. This equates to the scenario of a short drive, then a steep hill. This would be the number I'm interested in: what's the power limit on not-warmed-up batteries?
Back to Top
weber View Drop Down
Senior Member
Senior Member
Avatar

Joined: 23 January 2009
Location: Brisbane
Online Status: Offline
Posts: 650
  Quote weber Quote  Post ReplyReply Direct Link To This Post Posted: 17 July 2009 at 12:46pm
Originally posted by Nevilleh

Originally posted by weber

1. A voltage-sag or internal resistance figure is utterly meaningless if you don't know the internal temperature of the cell at the time. The figures can almost halve with a temperature increase of only about 10 degrees Celsius. One day we'll have the relationship worked out so we only need figures at one or two temperatures and we can predict it at any other.

Self-contradictory! How can it be "utterly meaningless" in one sentence and "almost halve" in the next?

Good point. Replace "utterly meaningless" with "fairly meaningless".

Sorry I'm addressing your posts in reverse order. I'll get there eventually. My point above is that internal resistance changes quite significantly with temperature, but I don't know the relationship yet. So you need to know the internal temperature for the measured result to be meaningful. More to come.
[Edit: formatting quotes properly]

Edited by weber - 17 July 2009 at 4:49pm
Working with Coulomb on converting an MX-5
Back to Top
Johny View Drop Down
AEVA Member
AEVA Member
Avatar

Joined: 23 June 2008
Location: Melbourne
Online Status: Offline
Posts: 1665
  Quote Johny Quote  Post ReplyReply Direct Link To This Post Posted: 17 July 2009 at 12:51pm
Hi guys. From my understanding Nevilleh was starting with a cell at near ambient then testing it to ascertain capacity. He used an assumption that internal heating would be minimal when performing short high-current bursts. Useful testing.

Weber's test (at least one of them), on the other hand, was to check what the cell did with different ambient temperatures. This was also useful since we have members in cold climates currently having problems. Also useful.

I know this is over simplified, perhaps a statement of goals at the beginning of such posts or tests might be prudent.
Back to Top
Nevilleh View Drop Down
Senior Member
Senior Member
Avatar

Joined: 15 January 2009
Location: Tauranga NZ
Online Status: Offline
Posts: 470
  Quote Nevilleh Quote  Post ReplyReply Direct Link To This Post Posted: 17 July 2009 at 1:02pm
Yes, the temp relationship would be handy to know.
I think I read somewhere on here that a guy with an operating vehicle found that his BMS gave a low voltage alarm on cold mornings. He also said the alarm point didn't change very quickly as he used the vehicle, implying that the cells were not warming up all that much with quite heavy current drains. He would have been sucking at least 100A to even drive the thing and that didn't seem to create a great deal of heat in the battery.
When I did my test I stated that the garage temp and hence the cells (been there for two weeks or more) was 17 deg and it does not change much even on cold nights as it is insulated and part of the house. The cell I tested did not get appreciably warm to the touch. Not scientific, I know, but enough to tell me that extreme heating wasn't going on. Next time I do it, I'll drill a hole in the plastic case and stick a thermometer in there! I'm not prepared to open the case and put a probe inside.
But if my internal res figure is near right, and I reckon it is, the internal heating from 24 watts for 23 minutes is not very great.

I appreciate all the great ideas and the work that is reported on this site. I am working here in quite an intellectual vaccuum and am entirely on my own as I don't know anyone else interested in this stuff, so this is the only way to absorb/express ideas!

I just want to add the

that I omitted previously!
Also, I set out to try and measure the internal res of an SE cell under a typical EV load and measured a TS one instead as the SE hasn't arrived yet. The comparison will be interesting and it will be done at the same Temp!!!!!

Edited by Nevilleh - 17 July 2009 at 1:09pm
Back to Top
 Post Reply Post Reply Page  123>

Forum Jump Forum Home Forum Permissions View Drop Down

Bulletin Board Software by Web Wiz Forums® version 9.07
Copyright ©2001-2008 Web Wiz

This page was generated in 0.156 seconds.